![]() 07/21/2014 at 21:10 • Filed to: None | ![]() | ![]() |
Sorry. I really hate to bring maths into this forum. But I am trying to teach myself calculus (because idiot) and this one question has me mighty confused.
XJ 220 for your time
Now with the question: 1334= -p^2-5p+1400.
The book says p = 6. I don't see how. I get (p+6)(p-1)
![]() 07/21/2014 at 21:11 |
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Nope, no engineers here.
edit: seriously though, maybe I can remember things... it's been a while
![]() 07/21/2014 at 21:11 |
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Would help if you posted the question, we are not THAT smart.
![]() 07/21/2014 at 21:12 |
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hmmmm
![]() 07/21/2014 at 21:13 |
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lol. 1334 = -p^2-5p+1400.
How can P be $6?
I get p = -6. (p+6)(p-1)
![]() 07/21/2014 at 21:15 |
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Let's see if this fancy aero degree learned me anything.
![]() 07/21/2014 at 21:17 |
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ok fixed. This is just algebra.
![]() 07/21/2014 at 21:18 |
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ok I put up the question. Just basic algebra, but since idiot cannot into factoring...much confusion.
![]() 07/21/2014 at 21:18 |
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Alright, after simplifying, I get 0=p^2 +5p -66
Plug it in to the quadratic equation [(-b +/- (b^2-4ac)^(1/2)]/2a
Then you get solutions of 6 and -11
EDIT: fixed... doing shit in your head can lead to errors...
![]() 07/21/2014 at 21:20 |
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well it's -p^2 -5p. But you have made me see the problem. Why did I think that 1400-1334 was 6. Fuck me I'm dumb.
![]() 07/21/2014 at 21:22 |
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Edit: I'm an idiot and can't do basic subtraction.
p^2 +5p -66 =0
(p-6)(p+11)=0
p=6 p=-11
![]() 07/21/2014 at 21:22 |
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check my reply again, you can get it, I just tried to do it in my head. hint... always write down all of your steps...
and no worries man, we've all been there
![]() 07/21/2014 at 21:27 |
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Many thanks man!! Got into a stupid loop trying to factor it when I can't even get the basic subtractions. when you get it to p^2+5p-66 it becomes obvious the factors are (P+11) (p-6) and therefore (there was limited domain due to application (price point) that p is 6.
![]() 07/21/2014 at 21:28 |
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The answer should be p=6 and p=-11. Set p^2 to be positive and set all on one side. You get
P^2 +5p - 66 = 0. Factor to get (p+11) and (p-6) = 0.
Therefore, p=6 and p=-11.
I'm beginning my masters in mech. Eng. In the fall. This had better be correct haha
![]() 07/21/2014 at 21:30 |
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Thanks. For some reason I confused myself by thinking 1400-1334 = 6 not 66. Then I was trying to factor...goodness.
Edit: I should add restrict domain (price) so yes p = -11 but restrict domain.
![]() 07/21/2014 at 21:33 |
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Nice! I actually just started doing my masters in Mech. E this summer after being out of it for a few years. And google is your friend ;)
http://www.math.com/students/calcu…
![]() 07/21/2014 at 21:34 |
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That was my problem. somehow this genius thought 1400-1334 was 6. Fuck.
![]() 07/21/2014 at 21:34 |
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Haha not a problem. It's always the easiest things that trip you up. Negative signs have always been the bane of my existence.
![]() 07/21/2014 at 21:36 |
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Fractions are the bane of mine.
![]() 07/21/2014 at 21:58 |
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Cool! What are you writing your thesis on, or are you going the non-thesis route?
![]() 07/21/2014 at 22:06 |
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My professor pretty much threw a thesis at me so it was hard to say no. I basically get to develop a computational toolbox that simulates everything going on inside of an Electrospray Ionization Mass Spectrometer so we can predict the outputs based on adjusting input conditions. Basically I have to use Navier-Stokes equations and Boltzmann a lot along with DSMC. I've also decided to do it in a year.
It's going to be a very long year.
How about you? What's your plan?
![]() 07/22/2014 at 00:25 |
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Oh wow! I hope you drink coffee if you plan to complete that in a year! But, that does sound interesting. As for myself, I am not sure yet as to the exact topic of my research/thesis. However, it is very likely that I will either be working in engine/combustion research or vehicle system modeling and simulation (in something like Matlab/Simulink). Conveniently, my university's mechanical engineering department places a fairly heavy emphasis on vehicle technologies, which is an area in which I would like to eventually work. And I will be doing it in two years, as I will also be teaching a class during this time.
![]() 07/22/2014 at 00:43 |
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Nice! That sounds really cool. My school focuses on aerospace more, so the models I am dealing with are more related to low-density gases with high speeds and vacuums...like space :D It does involve a lot of MatLab as well ;)
If you don't mind me asking, where are you going to school?
![]() 07/22/2014 at 01:27 |
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got to 4AC, mind wandered...
![]() 07/22/2014 at 21:48 |
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The University of Alabama. They paid for my undergraduate degree, and now they are paying for my master's degree. Which is nice. The fact that we completed a new $50ish million engine/combustion lab about a year and a half ago is an added bonus. You?
![]() 07/22/2014 at 23:21 |
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That sounds really awesome. I was always jealous of the schools with a sweet auto program.
I did my undergrad at Colorado School of Mines, which was rigorous and got me ready for the real world, but nothing really specialized.
Now I am at the University of Colorado Colorado Springs. Honestly I was surprised they even had a program. Turns out they have a lot of ties with the DoD and space aeronautic firms. Space! My specialty is literally called Space.